NettetSolution for #include using namespace std; int main int input[100], count, i, min; cout << "Enter Number of Elements in Array\n"; cin >> count; ... Sort the numbers from smallest to largest" << endl; cout << "4. Get the average of the array elements.\n" << … NettetExpert Answer. The theta notation of given fun () is g …. View the full answer. Transcribed image text: What is the time complexity of fun ()? int fun (int n) { int count = 0; for (int i = 0; i < n; i++) for (int j = i; j >0; i--) count = count + 1; return count; }

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Nettet#include void func() { int i = 0; i++; printf("i = %d\n",i); } int main() { func(); func(); func(); func(); return 0; } Here is the output. http://ideone.com/GDvnGp Here, the int variable i is declared inside the function func () and thus is a local variable for that function. Nettet9. aug. 2012 · The approach is to write a simple recursive function count (n) that counts the zeroes from 1 to n. The key observation is that if N ends in 9, e.g.: 123456789. You … drpciv dambovita programare online

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Nettet7. jul. 2013 · int *array = new int [n]; It declares a pointer to a dynamic array of type int and size n. A little more detailed answer: new allocates memory of size equal to sizeof … Nettet10. des. 2024 · int main () { int i,j,count; count=0; for (i=0; i<5; i++); { //do nothing } for (j=0;j<5;j++); { //do nothing } count++; printf ("%d",count); return 0; } both for loop do … Nettet17. nov. 2015 · 0 1 Here lets take eg : LET n = 10 initially: i = 10 (first loop) j = 0 < 10 (i) so it will loop from 0 to 9 times NOW AFTER NESTED LOOP GETS OVER THIS TAKES PLACE i /= 2 SO value of i = 5 (first loop ) 2 iteration. this time j will run from j = 0 < 5 (i) so it will loop from 0 to 5 times drpciv craiova programare online